When `1mol` of a monoatomic ideal gas at `TK` undergoes adiabatic change under a constant external pressure of `1atm`, changes volume from `1 L to 2L`. The final temperature (in K) would be

Options

A. `(T)/(2^(2//3)`
B. `T+(2)/(3xx0.0821)`
C. `T`
D. `T-(2)/(3xx0.0821)`

Answer

A

Explanation

`TV^(gamma-1)=`constant,`(T)/(T_("final"))=((V_(2))/(V_(1)))^(gamma-1)`
`(T)/(T_("Final"))=((2)/(1))^((5//3-1))=2^((2//3))`
`T_("Final")=(T)/(2^((2//3)))`