Pick out the incorrect statement for `XeF_(6)`

Options

A. `XeF_(6)` is hydrolysed partially to form `XeOF_(4)`
B. It reacts with `SiO_(2)` to form `XeOF_(4)`
C. On complete hydrolysis, it forms `XeO_(3)`
D. It acts as `F^(-)` acceptor when treated with alkali metal fluoride, but cannot act as `F^(-)` donor to form complexes.

Answer

D

Explanation

It acts as `F^(-)` donor with covalent pentafluorides.
`XeF_(6)+SbF_(5)to[XeF_(5)]^(+)[SbF_(6)]^(-)`
`XeF_(6)+AsF_(5)to[XeF_(5)]^(+)[AsF_(6)]^(-)`
it also acts as `F^(-)` acceptor.
`XeF_(6)+RbF to Rb^(+)[XeF_(7)]^-`
(a) `XeF_(6)+H_(2)O to XeOF_(4)+2HF`
(b) `2XeF_(6)+SiO_(2) to 2XeOF_(4)+SiF_(4)`
(c) `XeF_(6)+3H_(2)OtoXeO_(3)+6HF`