If 200 MeV energy is released per fissio...

If 200 MeV energy is released per fission of `._(92)U^(235)` How many fissions must occur per second to produce a power of 1m W?

A

`3.12xx10^(13)`

B

`3.12xx10^(3)`

C

`3.1xx10^(17)`

D

`3.12xx10^(19)`

Text Solution

Verified by Experts

The correct Answer is:

A

Total energy/s`=1000J`
Energy released /fission `=200MeV`
`=22xx1.6xx10^(-13)J`
`=3.2xx10^(-11)J`
`:.` Number of fission per second
`=1000/(3.2xx10^(-11))=3.12xx10^(13)`

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