In a communication system, operating at `lamda=700nm,` only 1% of the optical source frequency is the available channel band width. How many channels can be accommodated for transmitting the signal requiring an approximate band width of `4.5 MeV`?

Options

A. `8.5xx10^(5)`
B. `9.5xx10^(6)`
C. `9.5xx10^(5)`
D. `8.5xx10^(4)`

Answer

C

Explanation

Source frequency,
`v=c/(lamda)=(3xx10^(8))/(700xx10^(-9))=4.28xx10^(14)Hz`
and width of channel
`=1%` of the source frequency
`=1/100xx4.28xx10^(14)`
`=4.28xx10^(12)Hz`
Number of channels for the signal.
`=(4.28xx10^(12))/(4.5xx10^(6))=9.5xx10^(5)` Hz