If the temperature of a hot body is increased by `50%`, then the increase in the quantity of emitted heat radiation will be

Options

A. 1.25
B. 2
C. 3
D. 4

Answer

D

Explanation

As we know `Q prop T^(4)`
So `(Q_(1))/(Q_(2))=((T_(1))/(T_(2)))^(4)`
`implies(Q_(1))/(Q_(2))=(T/(T+T//2))^(4)=16/81`
`impliesQ_(2)=81/61Q_(1)`
% increase in energy
`=(Q_(2)-Q_(1))/(Q_(1))xx100=400%`