`RCONH_(2)+4NaOH+Br_(2) to RNH_(2) + 2NaBr+Na_(2)CO_(3)+2H_(2)O` Reaction is said

Options

A. Hofmann bromamide reaction
B. Schmidt reaction
C. Curtius reaction
D. Beckmann reaction

Explanation

To determine the name of the reaction given by the equation:

\[ \text{RCONH}_2 + 4\text{NaOH} + \text{Br}_2 \rightarrow \text{RNH}_2 + 2\text{NaBr} + \text{Na}_2\text{CO}_3 + 2\text{H}_2\text{O} \]

we will analyze the components and the nature of the reaction step by step.

### Step 1: Identify the Reactants
The reactants in the equation are:
- RCONH₂ (a primary amide)
- 4 NaOH (sodium hydroxide)
- Br₂ (bromine)

### Step 2: Analyze the Reaction Conditions
The reaction involves a primary amide reacting with sodium hydroxide and bromine. The presence of sodium hydroxide suggests that the reaction is likely to involve a hydrolysis step, while bromine indicates a halogenation process.

### Step 3: Identify the Products
The products of the reaction are:
- RNH₂ (a primary amine)
- 2 NaBr (sodium bromide)
- Na₂CO₃ (sodium carbonate)
- 2 H₂O (water)

### Step 4: Recognize the Type of Reaction
This reaction is characteristic of the **Hofmann degradation** (or Hofmann bromamide reaction). In this reaction, a primary amide is converted into a primary amine with the loss of one carbon atom. The reaction also produces sodium bromide and sodium carbonate as by-products.

### Step 5: Conclusion
Based on the analysis, the reaction can be classified as the **Hofmann Bromamide Reaction**.

### Final Answer
The reaction is called the **Hofmann Bromamide Reaction**.

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