The oxidation number and the electronic configuration of sulphur in `H_(2)SO_(4)` is

Options

A. `+4,1s^(2),2s^(2),2p^(6),3s^(2)`
B. `+2,1s^(2),2s^(2),2p^(6),3s^(2)`
C. `+3,1s^(2),2s^(2),2p^(6),3s^(2),3p^(1)`
D. `+6,1s^(2),2s^(2),2p^(6)

Answer

D

Explanation

Let the oxidation number of sulphur in `"H"_(2)"SO"_(4)` be x
then, `(2xx1)+x+(4x-2)=0`
`2+x+(-8)=0`
`x=8-2=+6`
The electronic configuration of sulphur
`""_(16)S=1s^(2),2s^(2),2p^(6),3s^(2),3p^(4)`
Electronic configuration of S in `H_(2)SO_(4)`
`16-6=10,1s^(2),2s^(2),2p^(6)`