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Propylene on hydrolysis with sulphuric a...

Propylene on hydrolysis with sulphuric acid forms

A

n-propyl alcohol

B

iso-propyl alcohol

C

ethyl alcohol

D

butyl alcohol

Text Solution

Verified by Experts

The correct Answer is:
B
`"CH"_(2)=underset("Propylene")("CH")-"CH"_(3)+"H"_(2)"O"overset("H"_(2)"SO"_(4))tounderset("Iso-propyl alcohol")("CH"_(3)-overset("OH")overset(|)("CH")-"CH"_(3))`
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