In an organic compound, C=68.5% and H=4....

In an organic compound, `C=68.5%` and `H=4.91%`. Which empirical formula is correct for it ?

A

`C_(6)H_(10)`

B

`C_(7)H_(6)O_(2)`

C

`C_(5)H_(8)O`

D

`C_(9)H_(3)O`

Text Solution

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The correct Answer is:

B

Hence, the empirical formula of the compound is `"C"_(7)"H"_(6)"O"_(2)`.

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