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The end product in the sequence would be...

The end product in the sequence would be
`C_(3)H_(7)OHoverset(H_(2)SO_(4))underset(170^(@)C)toAoverset(Br_(2))toBunderset(KOH)overset(Alc.)toC`

A

`CH_(3)-C-=CH`

B

`CH_(3)-underset(OH)underset(|)C=CH_(2)`

C

`CH_(2)=C=CH_(2)`

D

`CH_(3)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`"C"_(3)"H"_(7)"OH"overset("H"_(2)"SO"_(4))underset(170^(@)C)to"CH"_(3)-underset((A))("CH")="CH"_(2)overset("Br"_(2))tounderset((B))("CH"_(3)-overset("H")overset(|)underset("Br")underset(|)("C")-underset("H")underset(|)overset("Br")overset(|)-"H"overset("Alc.")underset("KOH")to)`
`"CH"_(3)-Cunderset((C))(-=)"CH"`
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