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A tripeptide (X) on partial hydrolysis g...

A tripeptide (X) on partial hydrolysis gave the dipeptides Gly-Cys and Cys-Gly, i.e.
`overset(o+)(NH_(3))-overset(CH_(2)CH_(2)COOH)overset(|)(CH)-underset("Glu-Cys")underset(O)underset(||)C-NH-overset(CH_(2)SH)overset(|)(CH)-underset(O)underset(||)(C)-overset(Theta)(O)`
`overset(o+)(NH_(3))-overset(CH_(2)SH)overset(|)(CH)-underset("Cys-Gly")underset(O)underset(||)(C)-NH-CH_(2)-underset(O)underset(||)(C)-overset(Theta)(O)`
Identify the tripeptide.

A

Gly-Glu-Cys

B

Gly-Glu-Cys

C

Cys-Gly-Glu

D

Cys-Glu-Gly

Text Solution

Verified by Experts

The correct Answer is:
A
Since, the tripeptide on hydrolysis gave two dipeptides Glu-Cys and Cys-Gly. Hence, cystine must be in between glutamic acid and glycine as given below.
`{:(" CH"_(2)"CH"_(2)"COOH"),(" "|),(""^(o+)"NH"_(3)"CH"-"C"-"NHCH"-"CNHCH"_(2)"CO"^(Theta)),(" "||" "|" "||" "||),(" O"" HSCH"_(2)" O O"):}`
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