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The area enclosed between the curve y=lo...

The area enclosed between the curve `y=log_(e)(x+e)` and the coordinate axes is

A

4 sq units

B

3 sq units

C

2 sq units

D

1 sq unit

Text Solution

Verified by Experts

The correct Answer is:
D
`A=int_(1-e)^(o)log_(e)(x+e)dx`

Put `x+e=timpliesdx=dt`
`:." "A=int_(1)^(e)logt" dt"=[tlogt-t]_(1)^(e)`
`=(e-e-0+1)=1" sq unit"`
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