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A five digit number is chosen at random....

A five digit number is chosen at random. The probability that all the digits are distinct and digits at odd places are odd and digits at even places are even, is

A

`(1)/(60)`

B

`(2)/(75)`

C

`(1)/(50)`

D

`(1)/(75)`

Text Solution

Verified by Experts

The correct Answer is:
D
Total number of 5 digit number
`9xx10xx10xx10xx10=90000`
Number of favourable numbers
`=5xx5xx4xx4xx3=1200`
Thus, required probability `=(1200)/(90000)`
`=(1)/(75)`
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