In which of the following compounds,nitrogen exhibits highest oxidation state?

Options

A. `N_(2)H_(4)`
B. `NH_(3)`
C. `N_(3)H`
D. `NH_(2)OH`

Answer

C

Explanation

` N_2 H _ 4 rArr 2x + 4 ( + 1 ) = 0 `
` rArr 2x + 4 = 0 `
` rArr x = - 2 `
` NH _ 3 rArr x + 3 ( + 1 ) = 0 rArr x = - 3 `
` NH _ 3 rArr 3x + 1 ( + 1 ) = 0 `
`rArr 3x + 1 = 0 rArr x = -1// 3 `
` NH _ 2 OH rArr x + 2 + 1 ( - 2 ) + 1 = 0 `
` rArr x + 1 = 0 rArr x = - 1 `
Thus, highest oxidation state is ` - 1// 3 `.