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The spin magnetic moment of cobalt in th...

The spin magnetic moment of cobalt in the compound `Hg[Co(SCN)_(4)]` is

A

`sqrt3`

B

`sqrt15`

C

`sqrt24`

D

`sqrt8`

Text Solution

Verified by Experts

The correct Answer is:
B
In Hg `[Co(SCN ) _ 4 ] ` , Co is present as ` Co^( 2 + ) `. The configuration of `Co ^( 2 + ) ` is given as following
`[Ar] 3d^ 7 4s^(0) , n = 3 `
` therefore ` Magnetic moment ` (mu ) = sqrt ( n ( n + 2 )) `
` sqrt ( 3 ( 3 + 2 )) = sqrt ( 15 ) BM `
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