The vapour pressure of benzene at 90^(@)...

The vapour pressure of benzene at `90^(@)C` is 1020 torr. A solution of 5g of a solute in 58.5 g benzene has a vapour pressure of 990 torr. The molecular weight of the solute is

78.2

148.3

204.2

226.66

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The correct Answer is:

`(p^(@)-p_(s))/(p^(@))=(wM)/(Wm)`
`rArr (1020-990)/(1020)=(5xx78)/(58.5 xx m)`
`therefore m=226.66`

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