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Let `f:(0,oo)to R and F(x)=int_(0)^(x) f(t)dt. " If " F(x^(2))=x^(2)(1+x)`, then f(4) equals

A

`(5)/(4)`

B

7

C

4

D

2

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The correct Answer is:
To solve the problem, we start with the given function \( F(x) = \int_0^x f(t) dt \) and the condition \( F(x^2) = x^2(1+x) \). We need to find \( f(4) \). ### Step-by-Step Solution: 1. **Differentiate Both Sides**: We start by differentiating the equation \( F(x^2) = x^2(1+x) \) with respect to \( x \). \[ \frac{d}{dx} F(x^2) = \frac{d}{dx} [x^2(1+x)] \] 2. **Apply the Chain Rule**: Using the chain rule on the left side, we have: \[ \frac{d}{dx} F(x^2) = f(x^2) \cdot \frac{d}{dx}(x^2) = f(x^2) \cdot 2x \] 3. **Differentiate the Right Side**: Now, differentiate the right side: \[ \frac{d}{dx} [x^2(1+x)] = 2x(1+x) + x^2 = 2x + 2x^2 \] 4. **Set the Derivatives Equal**: Now we equate both sides: \[ f(x^2) \cdot 2x = 2x + 2x^2 \] 5. **Solve for \( f(x^2) \)**: Dividing both sides by \( 2x \) (assuming \( x \neq 0 \)): \[ f(x^2) = 1 + x \] 6. **Substitute \( x = 2 \)**: We need to find \( f(4) \), which corresponds to \( f(x^2) \) when \( x = 2 \): \[ f(4) = f(2^2) = 1 + 2 = 3 \] ### Final Answer: Thus, the value of \( f(4) \) is \( \boxed{3} \).

To solve the problem, we start with the given function \( F(x) = \int_0^x f(t) dt \) and the condition \( F(x^2) = x^2(1+x) \). We need to find \( f(4) \). ### Step-by-Step Solution: 1. **Differentiate Both Sides**: We start by differentiating the equation \( F(x^2) = x^2(1+x) \) with respect to \( x \). \[ \frac{d}{dx} F(x^2) = \frac{d}{dx} [x^2(1+x)] ...
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-PRACTICE SET 16-Paper - 2 (MATHEMATICS )
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  4. lim(nto oo)1/n+(1)/(sqrt(n^(2)+n))+(1)/(sqrt(n^(2)+2n))+...(1)/(sqrt(n...

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  5. The area bounded by y = sin^(-1)x,x=(1)/(sqrt(2)) and X-axis is

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  6. The perpendicular distance between the line vecr = 2hati-2hatj+3hatk+l...

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  7. If the slope of one of the lines given by ax^(2)+2hxy+by^(2)=0 is 5 ti...

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  8. The derivative of f(x)=3|2+x| at the point x0=-3 is

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  10. Switching function of the network is

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  13. In the adjoining circuit, the output s is

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  14. The slope of tangent at (x,y) to a curve passing through (2, 1) is (x...

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