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In a travelling wave, y = 01 sin pi[x - ...

In a travelling wave, `y = 01 sin pi[x - 330t + (2)/(3)]`. The phase difference between `x_(1) = 3 and x_(2) = 35` m is

A

`pi//2`

B

`pi`

C

`3pi//2`

D

`2pi`

Text Solution

Verified by Experts

The correct Answer is:
A
Comparing given equation with
`y = A sin (kx -omegat + phi)`
`kx = pix`
`rArr k = pi`
`lambda = (2pi)/(k) = (2pi)/(pi) = 2m`
Phase difference, `trianglephi = (2pi)/(lambda) xx trianglex`
` = (2pi)/(2) (3.5-3) = (pi)/(2)`
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