Given `F = (a//t) + bt^2` where F denotes force and t time. The diamensions of a and b are respectively:

Options

A. `[LT^(-4)] and[LT^(-1)]`
B. `[LT^(-1)] and[LT^(-4)]`
C. `[MLT^(-4)] and[MLT^(-1)]`
D. `[MLT^(-1)] and[MLT^(-4)]`

Answer

D

Explanation

By the principle of dimensions homogenetiy.
`[F] = [aT^(-1)]`
`[MLT^(-2)] = a [T^(-1)]`
` a = [MLT^(-1)]`
Similarly for `b =[MLT^(-4)]`