In the shown arrangement of the experiment of the meter bridge if AC corroesponding to null deflection of galvanometer is x, what would be its value if the radius of the wire AB is doubled?
.

Options

A. `(x)/(2)`
B. `(x)/(4)`
C. 4x
D. x

Answer

D

Explanation

For the balanced metre bridge
`(P)/(Q) = (x)/((100 -x))`
When radius of bridge wire is
changed, there will be no change in the ratio of the resistance of two arms AC and BC. Thus in that case too,
`(P)/(Q) = (x)/((100-x))` i.e., AC = x lt