Critical temperature of `H_(2)O, NH_(3), CO_(2)` and `O_(2)` are 647 K, 405.6 K, 304.10 K and 1542 K respectively. If the cooling starts from 500 K to their critical temperature, the gas that lilquiefies first is

Options

A. `H_(2)O`
B. `NH_(3)`
C. `CO_(2)`
D. `O_(2)`

Answer

B

Explanation

Since, the cooling starts from 500 K, so water is not under consideration, As it is much easier to achieve 500 K from 405.6 K, So, `NH_(3)` will get liquified first.