IN which of the following pairs, the two species have identical bond order ?

Options

A. `N_(2)^(-), O_(2)^(2-)`
B. `N_(2)^(-), O_(2)^(-)`
C. `N_(2)^(-), O_(2)^(+)`
D. `O_(2)^(+), N_(2)^(2-)`

Answer

C

Explanation

Total number of electron in `N_(2)^(-)`
` = 7 + 7 + 1 = 15`
Total number of electron in
`N_(2)^(2-) = 7 + 7 + 2 =16`
Total number of electrons in
` O_(2)^(2-) = 8 + 8 + 1 = 17`
Total number of electrons in
` O_(2)^(2-) = 8 + 8 + 2 = 18`
Total number of electrons in
`O_(2)^(+) = 8 + 8-1 = 15`
As `N_(2)^(-) and O_(2)^(+)` contain the same total number of electrons, their MO electronic configuration will be same. Thus, `N_(2)^(-) and O_(2)^(+)` have the same bond order.