A black body emits radiations of maximum intensity at a wavelength of Å 5000 , when the temperature of the body is `1227^(@)C`. If the temperature of the body is increased by `1000^(@)C` , the maximum intensity of emitted radiation would be observed at

Options

A. `2754.8 Å`
B. `3000Å`
C. `3500Å`
D. `4000Å`

Answer

B

Explanation

From Wien's displacement law
`lamda_(1)T_(1)=lamda_(2)T_(2)`
`5000(1227+273)=lamda_(2)(2227+273)`
`5000xx1500=lamda_(2)xx2500`
`therefore lamda_(2)=(5000xx1500)/(2500)=3000Å`