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This time period of a particle undergoin...

This time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 `ms^(-1)`. The amplitude is

A

0.36 m

B

0.88 m

C

0.72 m

D

1.44 m

Text Solution

Verified by Experts

The correct Answer is:
D

`v=Aomegacos omegat`
`04=A(2pi)/(16)cos ""((2pi)/(16)xx2)`
`04=Api/8 cos ""pi/4`
`0.4=Api/8cos pi/4`
`0.4=A pi/8(1)/(sqrt2)`
`A=(04xx8xxsqrt2)/(pi)=1.44m`
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