A ray of light falls on a transparent glass slab of refractive index `1.62`. If the reflected ray and the refracted rays are mutually perpendicular, what is the angle of refraction ?

Options

A. `tan^(-1)(162)`
B. `tan^(-1)((1)/(1.62))`
C. `tan^(-1)(1.33)`
D. `tan^(-1)((1)/(1.33))`

Answer

A

Explanation

Breqster discovered that when a beam of nupolarised light is reflected from a transparent medium (refractive index `=mu),` the reflected ligh is comletely plane polarised at a certain angle of incidence (called the angle of polarisation `theta_(rho))`
Aslo, `mu=tan theta_(rho)`
`therefore` Here, `theta _(rho)=theta_(i)=tan^(-1)(1.62)`