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The kinetic energy of an electron with d...

The kinetic energy of an electron with de - Broglie wavelength of `0.3 nanometre` is

A

0.168 ev

B

16.8 ev

C

1.68 ev

D

2.5 ev

Text Solution

Verified by Experts

The correct Answer is:
B
`lamda=(h)/(sqrt(2mE))impliesE=(h^(2))/(2mlamda^(2))`
`((6.6xx10^(-34))^(2))/(2xx9.1xx10^(-31)xx(0.3xx10^(-9))^(2))`
`=2.65xx10^(-18)J=16.8eV`
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