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If the sum of n terms of an A.P is 2n + ...

If the sum of n terms of an A.P is `2n + 3n^2` , find the `r^(th)` term

A

`2r+3r^(2)`

B

`3r^(2)-4r+1

C

`6r-1`

D

`4r+1`

Text Solution

Verified by Experts

The correct Answer is:
C

Let `S_(n)=2n+2n^(2)`
Now, `S_(n-1)=2(n-1)+3(n-1)^(2)`
`=20-2+3n^(2)+3-6n`
`=3n^(2)-4n+1`
`thereforeT_(n)=S_(n)-S_(n-1)`
`=2n +2n^(2)-(3n^(2)-4n+1)`
`=6n-1`
`T_(r)=6r-1`
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