The equation to the perpendicular from the point `(alpha, beta gamma)` to the plane `ax+by+cz+d=0` is

Options

A. `(x-a)/(a alpha) =(y-b)/(b beta)=(z-c)/(c gamma)`
B. `x/a=y/b=z/c`
C. `(x-alpha)/(a)=(y-beta)/(b)=(z-lamda)/©`
D. `(x)/(alpha)=(y)/(beta)=(z)/(gamma)`

Answer

C

Explanation

Equation of line which is passing through `(alpha, beta, gamma)` and perpendicular to the plane `ax+by+cz+d=0` is
`(x-alpha)/(a)=(y-beta)/(b)=(z-gamma)/(c)`