A body is executing simple harmonic motion with an angular frequency s rad/2 . The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm , is

Options

A. 40 mm/s
B. 60 mm/s
C. 113 mm/s
D. 120 mm/s

Answer

C

Explanation

We know that, the particle velocity
`v=omega sqrt(A^(2)-y^(2))`
Given that `omega=2` rad/s,
A = 60 mm = 0.06 m
and `y=20` mm = 0.02 m
`:." "v=2sqrt((0.06)^(2)-(0.02)^(2))`
`=0.113" m"//"s"`
`=113" mm"//"s"`