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Three forces start acting simultaneously on a particle moving with velocity `vec(v)`. These forces are represented in magnitude and direction by the three sides os a triangle ABC (as shown). The particle will now move with velocity.

A

less than v

B

greater than v

C

v in the direction of largest force BC

D

v remaining unchanged

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The correct Answer is:
D

Resultant force is zero, as three forces acting on the particle can be represented in magnitude and direction by three sides of a triangle in order. Hence, by Newton's 2nd law `(F=m(dv)/(dt))`, particle velocity (v) will be same.
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