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The point (5,-7) lies outside the circle...

The point `(5,-7)` lies outside the circle

A

`x^(2)+y^(2)-8x=0`

B

`x^(2)+y^(2)-5x+7y=0`

C

`x^(2)+y^(2)-5x+7y-1=0`

D

`x^(2)+Y^(2)-8x+7y-2=0`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If the point (3,4) lies inside and the point (-3,-4) lies outside the circle x ^(2) + y ^(2) - 7x +5y -p=0, then the set of all possible values of p is

    A
    `(24,25)`
    B
    `(25,26)`
    C
    `(24,26)`
    D
    `(0,24)`

  • The set of values of 'a' for which the point (a-1, a+1) lies outside the circle x^(2)+y^(2)=8 and inside the circle x^(2)+y^(2)-12x+12y-62=0 , is

    A
    `(-oo, -sqrt(3) ) uu(sqrt(3), oo)`
    B
    `(-3sqrt(2), 3 sqrt(2))`
    C
    `(-3sqrt(2), -sqrt(3))uu(sqrt(3), 3sqrt(2))`
    D
    none of these

  • The point (lambda,4) lies outside the circles S_(1)=x^(2)+y^(2)+10x=0 and S_(2)=x^(2)+y^(2)-12x+20=0 then lambda belong to

    A
    `(-oo, -8) cup (-2, oo)`
    B
    `(-8, -2)`
    C
    `(-oo,-8) cup (-2, 6) cup (6, oo)`
    D
    none

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