Home
Class 12
PHYSICS
If the change in the value of g at a hei...

If the change in the value of g at a height h above the surface of the earth is the same as at a depth x below it, then (both x and h being much smaller than the radius of the earth)

A

x=h

B

x=2xh

C

`x=(h)/(2)`

D

`x=h^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to establish the relationship between the change in the value of gravitational acceleration (g) at a height \( h \) above the Earth's surface and at a depth \( x \) below it. We will use the formulas for gravitational acceleration at height and depth. ### Step-by-Step Solution: 1. **Understanding the Problem**: We need to find the relationship between height \( h \) and depth \( x \) such that the change in gravitational acceleration at height \( h \) is equal to the change at depth \( x \). 2. **Gravitational Acceleration at Height**: The formula for gravitational acceleration at a height \( h \) above the Earth's surface is given by: \[ g_h = g \left(1 - \frac{2h}{R}\right) \] where \( g \) is the gravitational acceleration at the surface and \( R \) is the radius of the Earth. 3. **Gravitational Acceleration at Depth**: The formula for gravitational acceleration at a depth \( x \) below the Earth's surface is given by: \[ g_x = g \left(1 - \frac{x}{R}\right) \] 4. **Setting the Changes Equal**: According to the problem, the change in gravitational acceleration at height \( h \) is equal to the change at depth \( x \): \[ g - g_h = g - g_x \] This simplifies to: \[ g_h = g_x \] 5. **Substituting the Formulas**: Now, we substitute the expressions for \( g_h \) and \( g_x \): \[ g \left(1 - \frac{2h}{R}\right) = g \left(1 - \frac{x}{R}\right) \] 6. **Canceling Common Terms**: Since \( g \) is common on both sides, we can cancel it out: \[ 1 - \frac{2h}{R} = 1 - \frac{x}{R} \] 7. **Rearranging the Equation**: By rearranging the equation, we get: \[ -\frac{2h}{R} = -\frac{x}{R} \] This simplifies to: \[ 2h = x \] 8. **Final Relationship**: Therefore, we find the relationship between depth \( x \) and height \( h \): \[ x = 2h \] ### Conclusion: The relationship between the height \( h \) above the Earth's surface and the depth \( x \) below it is given by: \[ x = 2h \]
Promotional Banner

Topper's Solved these Questions

  • PRACTICE SET 22

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Physics & chemistry|1 Videos
  • PRACTICE SET 24

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Paper 1 (Physics and Chemistry)|50 Videos

Similar Questions

Explore conceptually related problems

If the change in the value of g at a height h above the surface of earth is the same as at a depth d below it (both h and d are much smaller than the radius of the earth), then

The change in the value of g at a height h above the surface of the earth is the same as at a depth d below the surface of earth. When both d and h are much smaller than the radius of earth, then which one of the following is correct ?

The change in the value of g at a height h above the surface of the earth is the same as at a depth d below the surface of earth. When both d and h are much smaller than the radius of earth, then which one of the following is correct?

The change in the value of 'g' at a height 'h' above the surface of the earth is the same as at a depth 'd' below the surface of earth. When both 'd' and 'h' are much smaller then the radius of earth, then which one of the following is correct?

The acceleration due to gravity at a height h above the surface of the earth has the same value as that at depth d= ____below the earth surface.

The acceleration due to gravity at a height 1 km above the earth is the same as at a depth d below the surface of earth

The acceleration due to gravity at a height 1km above the earth is the same as at a depth d below the surface of earth. Then :

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-PRACTICE SET 23-Paper-1(PHYSICS & CHEMISTRY)
  1. Long distance short-wave radio broadcasting uses

    Text Solution

    |

  2. The dimensional formula for inductance is

    Text Solution

    |

  3. If the pressure at half of the lake is equal to 1/3 pressure at the bo...

    Text Solution

    |

  4. To get an output 1 from the circuit shown in the figure, the input mus...

    Text Solution

    |

  5. The capacitance of an air filled parallel plate capacitor is 10 muF. T...

    Text Solution

    |

  6. A light wave is incident normally over a slit of width 24xx10^-5cm. Th...

    Text Solution

    |

  7. In an induction coil, the coefficient of mutual induction is 4 H. If a...

    Text Solution

    |

  8. Water is flowing through a pipe of constant cross-section. At some poi...

    Text Solution

    |

  9. In a biprism experiment, the wavelenght of monochromatic light is 6000...

    Text Solution

    |

  10. A wheel having moment of inertia 2 kg m^(2) about its vertical axis, r...

    Text Solution

    |

  11. Two particles of equal mass (m) each move in a circle of radius (r) un...

    Text Solution

    |

  12. A force of 1200 N acts on a 0.5 kg steel ball as a result of collision...

    Text Solution

    |

  13. A block of mass 2 kg rests on a horizontal surface. If a horizontal fo...

    Text Solution

    |

  14. The photoelectric threshold of a certain metal is 3000A. If the radiat...

    Text Solution

    |

  15. If the change in the value of g at a height h above the surface of the...

    Text Solution

    |

  16. The component of vector A=(a(x)hati+a(y)hatka(z)hatk) along the direct...

    Text Solution

    |

  17. lonization energy of an electron present in the second Bohr's orbit of...

    Text Solution

    |

  18. In a seconds pendulum, mass of bob is 30 gm . If it is replaced by 90 ...

    Text Solution

    |

  19. A magnetic field of 2xx10^(-2)T acts at right angles to a coil of area...

    Text Solution

    |

  20. The resultant of two vectors vec(P) and vec(Q) is vec(R ). If the magn...

    Text Solution

    |