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Circle x^2 + y^2 - 2x - lambdax - 1 = 0 ...

Circle `x^2 + y^2 - 2x - lambdax - 1 = 0` passes through to fixed points, coordinates of the points are

A

`(0 pm 1)`

B

`(pm 1,0) `

C

(0,1) and (0,2)

D

(0,-1) and (0,-2)

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The correct Answer is:
a
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