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The period of sin^(2) theta , is...

The period of `sin^(2) theta` , is

A

`pi^(2)`

B

`pi`

C

`2pi`

D

`(pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Since, `sin^(2)theta=(1-cos2theta)/(2)=(1)/(2)-(1)/(2)cos2theta`
`:." Period of "sin^(2)theta=(2pi)/(2)=pi`
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