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Find the range of function, f: [0,1] -> ...

Find the range of function, f: [0,1] -> R, `f(x)= x^3-x^2+4x+2sin^-1x .`

A

`[-(pi+2),0]`

B

`[0,4+pi]`

C

`[2,3]`

D

`[0,2+pi]`

Text Solution

Verified by Experts

The correct Answer is:
B
`f:[0,1]toR" such that "f(x)=x^(3)-x^(2)+4x+2sin^(-1)x`
`:." "f(0)=0" and "f(1)=4+pi`
Since, it is defined for all values of R.
`:." Range "=[0,4+pi]`
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