Home
Class 12
MATHS
Three of the six vertices of a regular h...

Three of the six vertices of a regular hexagon are chosen the random. What is the probability that the triangle with these vertices is equilateral.

A

`(1)/(2)`

B

`(1)/(5)`

C

`(1)/(10)`

D

`(1)/(20)`

Text Solution

Verified by Experts

The correct Answer is:
C
In a regular hexagon, there are two equilateral triangles are possible.
`therefore` Required probability `=(2)/(.^(6)C_(3))=(2)/((6xx5xx4)/(3xx2))=(2)/(20)=(1)/(10)`
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PRACTICE EXERCISE (Exercies 2 (MISCELLANEOUS PROBLEMS))|30 Videos

  • PROBABILITY

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 1 (TOPICAL PROBLEMS)|44 Videos

  • PRACTICE SET 24

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Paper 2 (Mathmatics)|50 Videos

  • SEQUENCES AND SERIES

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise EXERCISE 31|1 Videos

Similar Questions

Explore conceptually related problems

Three of six vertices of a regular hexagon are chosen at random.The probability that the triangle with three vertices is equilateral is (a) (1)/(2) (b) (1)/(5) (c) (1)/(10) (d) (1)/(20)

Three vertices are chosen at random from the vertices of a regular hexagon then The probability that the triangle with these vertices is an equilateral triangle is equal to

If three vertices of a regular hexagon are chosen at random, then the chance that they form an equilateral triangle is :

If four vertices a regular octagon are chosen at random, then the probability that the quadrilateral formed by them is a rectangle is

Two vertices of an equilateral triangle are origin and (4, 0). What is the area of the triangle ?