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If n integers taken art random are multi...

If `n` integers taken art random are multiplied together , then the probability that eh last digit of the product is 1, 3, 7, or 9 is

A

`(2^(n))/(5^(n))`

B

`(4^(n)-2^(n))/(5^(n))`

C

`(4^(n))/(5^(n))`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

Clearly, the last digit of the product will be 1, 3, 7 or 9 iff each of the n positive integers ends in 1, 3, 7 or 9.
Now, the probability of an integer ending in 1, 3, 7 or 9 is `(4)/(10)=(2)/(5)`.
Therefore, the probability that the last digit of the product of n integers ending in 1, 3, 7 or 9 is `((2)/(5))^(n)`
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