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Probability of all 3-digit numbers havin...

Probability of all 3-digit numbers having all the digits same is

A

`(1)/(100)`

B

`(3)/(100)`

C

`(7)/(100)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Total number of 3-digit = 900
Number of favourable cases = 9
`therefore` Required probability `=(9)/(900)=(1)/(100)`
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