A family has two children. What is the probability that both the children are boys given that at least one of them is a boy?

Options

A. `(1)/(2)`
B. `(1)/(4)`
C. `(1)/(3)`
D. None of these

Answer

C

Explanation

Total cases are BB,BG,CD,GG = 4
Let P(A) = Probability of a boy in two children `= (3)/(4)`
and P(B) = Probability that the both child are a boys `= (1)/(4)`
Here, `P(A nn B) =(1)/(4)`
`therefore " " P((B)/(A))=(P(A nn B))/(P(A))=((1)/(4))/((3)/(4))=(1)/(3)`