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A bag contains 5 white and 3 black balls...

A bag contains 5 white and 3 black balls. Four balls are successively drawn out without replacement. What is the probability that they are alternately of different colours?

A

`(1)/(196)`

B

`(2)/(7)`

C

`(1)/(7)`

D

`(13)/(56)`

Text Solution

Verified by Experts

The correct Answer is:
C
Required probability `= P(WBWB)+ P(BWBW)`
`= (5)/(8)xx(3)/(7)xx(4)/(6)xx(2)/(5)+(3)/(8)xx(5)/(7)xx(2)/(6)xx(4)/(5)`
`=2((5xx3xx4xx2)/(8xx7xx6xx5))=(1)/(7)`
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