If A and B are mutually exclusive events with `P(B) ne 1, " then " P(A//overline(B))`=

Options

A. `(1)/(P(B))`
B. `(1)/(1-P(B))`
C. `(P(A))/(P(B))`
D. `(P(A))/(1-P(B))`

Answer

D

Explanation

Given, A and B are mutually exclusive events.
`therefore P(A nn B) = 0`
Now, `P(A// bar(B))=(P(A nn bar(B)))/(P(bar(B)))=(P(A)-P(A nn B))/(P(bar(B)))=(P(A))/(1-P(B))`