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~(pvvq)vv(~p^^q) is equivalent to...

`~(pvvq)vv(~p^^q)` is equivalent to

A

p

B

`~p`

C

q

D

`~q`

Text Solution

Verified by Experts

The correct Answer is:
B
`~(p vv q)vv(~p ^^ q)-= (~p ^^ ~q)vv (~p ^^ q)`
`-= ~p ^^(~q vv q)-= ~p`
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