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For integers m and n, both greater than ...

For integers m and n, both greater than 1, consider the following three statements
P : m divides n, Q : m divides `n^(2)` and R : m is prime, then

A

`Q ^^ R to P`

B

`P ^^ Q to R`

C

`Q to R`

D

`Q to P`

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The correct Answer is:
To analyze the statements given in the question, we need to understand the implications of each statement and how they relate to one another. Let's denote the statements as follows: - P: m divides n (m | n) - Q: m divides n² (m | n²) - R: m is prime We want to determine the logical relationships among these statements. ### Step 1: Understanding the implications of the statements 1. **If m divides n (P)**, then we can express n as: \[ n = k \cdot m \quad \text{for some integer } k \] 2. **Now, if m divides n, we can analyze Q**: \[ n^2 = (k \cdot m)^2 = k^2 \cdot m^2 \] Since \(m^2\) is clearly divisible by \(m\), it follows that: \[ m \text{ divides } n^2 \quad \text{(Q is true)} \] Therefore, if P is true, Q must also be true. ### Step 2: Analyzing the relationship between Q and R 3. **Now consider R**: If m is prime, then it can only divide n or n² if n is a multiple of m. However, the converse is not necessarily true. Just because m divides n² does not imply that m is prime. ### Step 3: Exploring the implications of Q 4. **If m divides n² (Q)**, we can analyze whether this implies P or R: - If \(m\) divides \(n^2\), it does not necessarily mean that \(m\) divides \(n\). For example, if \(m = 4\) and \(n = 2\), then \(4\) divides \(2^2 = 4\) (Q is true) but \(4\) does not divide \(2\) (P is false). - Therefore, Q does not imply P. ### Step 4: Exploring the implications of R 5. **If m is prime (R)**, we need to check if it implies P or Q: - If \(m\) is prime and divides \(n\), then it must also divide \(n^2\) since \(n^2\) is a product of \(n\) with itself. Thus, if R is true, then both P and Q are true. ### Conclusion From the analysis above, we can summarize the implications: - If P is true, then Q is true. - If R is true, then both P and Q are true. - Q does not necessarily imply P or R. Thus, the correct logical relationship among the statements is: - Q and R imply P. ### Final Answer The correct option is: **Q and R conditional P**. ---

To analyze the statements given in the question, we need to understand the implications of each statement and how they relate to one another. Let's denote the statements as follows: - P: m divides n (m | n) - Q: m divides n² (m | n²) - R: m is prime We want to determine the logical relationships among these statements. ...
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-MATHEMATICAL LOGIC -PRACTICE EXERCISE (Exercies 2 (MISCELLANEOUS PROBLEMS))
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  2. Among the following statements, which is a tautology ?

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  3. Which of the following is not always true ?

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  4. Converse of the statement ''If a number x is even, then x^(2) is even'...

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  5. If p to (~ p vvq) is false, the truth values of p and q are , respecti...

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  6. The truth values of p,q and r for which (p ^^ q)vv(~r) has truth value...

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  7. p vv ~(p ^^ q) is a

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  8. The false statement among the following is

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  9. Which of the following is true for any two statements p and q ?

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  10. The proposition (p to ~p) ^^ (~p to p) is a

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  11. For integers m and n, both greater than 1, consider the following thre...

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  12. The statement ~(p harr ~q) is

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  13. ~[(~p)^^q] is logocally equivalent to

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  14. The statement p to(q to p) is equivalent to

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  15. If S(p,q,r)=(~p)vv(~(q ^^ r)) is a compound statement, then S(~p,~q,~r...

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  16. ~(p vv q)vv (~p ^^ q) is logically equivalent to

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  17. Dual of (x vv y) ^^ (x vv 1) = x vv x ^^ y vv y is

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  18. ~[(~p)^^q] is logocally equivalent to

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  19. The negation of ~ svv(~ r^^s) is equivalent to :

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  20. Given statement is 'if x = y, then x^(2) = y^(2), and the statement ar...

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