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Dual of (x vv y) ^^ (x' vv 1) is...

Dual of `(x vv y) ^^ (x' vv 1)` is

A

`(x ^^ y) vv (x' ^^ 0)`

B

`(x ^^ y) (x' ^^ 1)`

C

`(x ^^ y) vv (x ^^ 1)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Dual of `(x vv y) ^^ (x' vv 1)` is obtained by replacing `'vv'` by `'^^', '^^'` by `'vv'` and 1 by 0 i.e., dual is `(x ^^ y) vv (x' ^^ 0)`.
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