If tan2x="tan"(2)/(x), then the value o...

If `tan2x="tan"(2)/(x)`, then the value of x is

A

`(npi+-sqrt(n^(2)pi^(2)+16))/(4)`

B

`(npi)/(4)`

C

`(npi+-sqrt(n^(2)pi^(2)-16))/(4)`

D

None of these

Verified by Experts

The correct Answer is:

A

Since ,tan `2x="tan"(2)/(x)`
`rArr2x=npi+(2)/(x)rArr2x^(2)-npix-2=0`
`rArrx=(npi+-sqrt(n^(2)pi^(2)+16))/(4)`

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