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The root of the equation 1-costheta=sint...

The root of the equation `1-costheta=sintheta*"sin"(theta)/(2)` is

A

`kpi,kinI`

B

`2kpi,kinI`

C

`k(pi)/(2),kinI`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Given , `1-costheta=sintheta*"sin"(theta)/(2)`
`rArr2"sin"^(2)(theta)/(2)=2"sin"(theta)/(2)*"cos"(theta)/(2)*"sin"(theta)/(2)`
`rArr2"sin"^(2)(theta)/(2)[1-"cos"(theta)/(2)]=0`
`rArr"sin"(theta)/(2)=0or2"sin"^(2)(theta)/(4)=0`
`(theta)/(2)=kpior(theta)/(4)=kpi`
Hence , `theta=2kpiortheta=4kpi,kinI`
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