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{x inR:cos2x+2cos^(2)x=2} is equal to...

`{x inR:cos2x+2cos^(2)x=2}` is equal to

A

`{2npi+(pi)/(3):ninZ}`

B

`{npi+-(pi)/(6):ninZ}`

C

`{npi+(pi)/(3):ninZ}`

D

`{2npi-(pi)/(3):ninZ}`

Text Solution

Verified by Experts

The correct Answer is:
B
Given , `2cos^(2)x+2cos^(2)x-1=2`
`rArrcosx=+-(sqrt(3))/(2)`
`thereforex=npi+-(pi)/(6):ninZ`
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