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The genral value of theta satisfying sin...

The genral value of `theta` satisfying `sin^2theta+sintheta=2` is

A

`npi+(-1)^(n)(pi)/(6)`

B

`2npi+(pi)/(4)`

C

`npi+(-1)^(n)(pi)/(2)`

D

`npi+(-1)^(n)(pi)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
We have ,`sin^(2)theta+sintheta-2=0`
`rArr(sintheta-1)(sintheta+2)=0`
`sintheta=1,sintheta=-2`
But `sinthetane-2`
`thereforesintheta=1="sin"(pi)/(2)`
`rArrtheta=npi+(-1)^(n)(pi)/(2)`
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