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If tan((alphapi)/(4))=cot((betapi)/(4)),...

If `tan((alphapi)/(4))=cot((betapi)/(4)),` then

A

`alpha+beta=0`

B

`alpha+beta=2n`

C

`alpha+beta=2n+1`

D

`alpha+beta=2(2n+1),AAninI`

Text Solution

Verified by Experts

The correct Answer is:
D

Given , `tan((alphapi)/(4))=tan((pi)/(2)-(beta)/(4))`
`(alphapi)/(4)=npi+(pi)/(2)-(betapi)/(4)`
`rArr(alpha+beta)(pi)/(4)=((2n+1)/(2))pi`
`rArralpha+beta=2(2n+1),AA ninI`
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