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If one side of a triangle is double the ...

If one side of a triangle is double the other, and the angles on opposite sides differ by `60^0,` then the triangle is

A

obtuse angled

B

acute angled

C

isosceles

D

right angled

Text Solution

Verified by Experts

The correct Answer is:
D
Given , `A-B=60^(@)`
By sine rule ,

`(2a)/(sinA)=(a)/(sinB)`
`rArrsinA-2sinB=0`
`rArrsin60^(@)cosB+cos60^(@)sinB-2sin=0`
`rArrsqrt(3)[cos(60^(@)+B)]=0`
`rArr60^(@)+b=90^(@)`
`rArrB=30^(@)rArrA=90^(@)`
Hence , it is right angled triangle.
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